Materials:
- rocket
- timer
- cap
- wooden stnd
- nails
- scale
- measuring tool
- wooden triangle
- Horizontal:
- change in X= ?
- t= 3.84s
- Vi= ?
- Vertical:
- A= -9.8 m/s
- t=3.84s
- Vi= ?
- Vf= ?
We are assigned an angle. In order to collect data, we launched the rocket at 10 degree angle difference from the angle we are trying to solve for. Our groups goal was to predict the displacement of the rocket if it was launched at a 35 degree angle.
Video:
Here is a link showing a rocket being shot vertically into the air. In our experiment, we shot the rockets on an angle horizontally. During our experiment, our video cut our rocket out of the shot but this one can be used for understanding of the experiment.
https://www.youtube.com/watch?v=x3Xh00Jn8Bs
First we made a graph of the velocity on an angle and solved using cosign to find Vix and Viy. All of the calculations below are for a 35 degree angle.
cos 55= 10.94/x
x= 10.94/ cos 35
Vi= 19.06
cos 35= Viy/ 19.06
Viy= 15.6
Next, our group made calculations for 25 degree angle.
cos 65= Vix/ 19.06
Vix= 8.05
cos 25= Viy/ 19.06
Viy= 17.27
Next, we plugged in the Viy to the displacement equation to solve for time.
change in X= 1/2at^2+ Vit
0= 1/2(-10)t^2 + 17.27
-5t^2+ 17.27t + 0
Since this equation cannot be factor or simplfiied further, we plugged into the quadratic formula and got t= 3.45.
Next, we plugged in the Vix into the horizontal equation for displacement.
8.05 = change Xx/ 3.45
change in Xx= 2.78m
We found the precent error by subtracting the actual from the predicted measurement, and then dividing it by the predicted.
27.2 - 29 / 27.2 = 6.6% error
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